Avatar for Username

Pretraži podršku

Izbjegni prevare podrške. Nikad te nećemo tražiti da nas nazoveš, da nam pošalješ telefonski broj ili da podijeliš osobne podatke. Prijavi sumnjive radnje pomoću opcije „Prijavi zlouporabu”.

Saznaj više

Ova tema je arhivirana. Postavi novo pitanje ako trebaš pomoć.

How to navigate to a site without using the .com or .org etc. extension?

  • 2 odgovora
  • 22 imaju ovaj problem
  • 2 prikaza
  • Posljednji odgovor od Rvreezen

Rvreezen
Rvreezen
more options

I have downloaded the newest version of Firefox for windows 7 since I had to reinstall my laptop. Now however if I type in a company name or a site like hotmail or ebay without the .com extention it will go to google as if it was a search order. The past version installed on my laptop would automatically send me to the website of hotmail of ebay or any other page I typed.

Where can I find that function again it was really great!

Thanks for helping in advance.

I have downloaded the newest version of Firefox for windows 7 since I had to reinstall my laptop. Now however if I type in a company name or a site like hotmail or ebay without the .com extention it will go to google as if it was a search order. The past version installed on my laptop would automatically send me to the website of hotmail of ebay or any other page I typed. Where can I find that function again it was really great! Thanks for helping in advance.

Izabrano rješenje

Firefox 4.0 doesn't have the Google I'm feeling lucky search in the URL bar as previous versions did.
https://addons.mozilla.org/en-US/firefox/addon/luckybar/

Pročitaj ovaj odgovor u kontekstu 👍 4

Svi odgovori (2)

the-edmeister
the-edmeister
  • Moderator
more options

Odabrano rješenje

Firefox 4.0 doesn't have the Google I'm feeling lucky search in the URL bar as previous versions did.
https://addons.mozilla.org/en-US/firefox/addon/luckybar/

Rvreezen
Rvreezen Vlasnik pitanja
more options

Thanks! Installed in right away. It works again just like before. Thanks for your valuable input.